Q: How many liters of an acid solution with no salt content should be mixed with 35 liters of a saline solution with 40% salt content to yield a solution that is 32% salt?
(Target Audience: GMAT)
A. 4.12
B. 8.75
C. 18
D. 35
E. 43.75
Answer : Option B
Explanation : Generic Way
Let the quantity of solution with no salt = x
Quantity of salt in 0% saline solution = 0% of x = 0 ltrs
Quantity of salt in 40% saline solution = 40% of 35 = 14 ltrs.
Total quantity of salt = 0 + 14 = 14 ltrs
Quantity of salt after mixing two solution = 32% of total quantity
= 32% of (x+35)
Therefore, 14 = 32% of (x+35)
Or, 14 = 32 x 5)
100 * ( + 3
Or, 32 = x+35
14*100
Or, x = 32 -35 = 8.75 ltrs
14*100
OPTION B
Explanation : HolaMaven Way
